banner



1-4 Exercises Guided Practice Geometry

Try Information technology

11.one Systems of Linear Equations: Two Variables

2.

The solution to the organisation is the ordered pair ( −5 , 3 ) . ( −5 , iii ) .

6.

No solution. It is an inconsistent organisation.

seven.

The organization is dependent and then there are infinite solutions of the course ( x , 2 10 + 5 ) . ( x , 2 x + five ) .

viii.

700 children, 950 adults

11.two Systems of Linear Equations: Three Variables

3.

Space number of solutions of the form ( ten , 4 ten −xi , −5 10 + 18 ) . ( x , 4 x −xi , −five x + 18 ) .

11.3 Systems of Nonlinear Equations and Inequalities: 2 Variables

1.

( one 2 , 1 ii ) ( ane 2 , 1 2 ) and ( two , viii ) ( two , 8 )

3.

{ ( 1 , three ) , ( one , −3 ) , ( −1 , 3 ) , ( −ane , −three ) } { ( 1 , three ) , ( 1 , −iii ) , ( −1 , 3 ) , ( −1 , −3 ) }

11.4 Partial Fractions

1.

three ten −iii ii ten −2 3 ten −3 ii x −2

2.

6 ten −1 five ( 10 −1 ) 2 6 x −1 v ( x −1 ) 2

3.

iii x −ane + 2 x −4 x ii + 1 3 x −one + 2 x −4 x ii + 1

4.

ten −2 ten 2 −two ten + three + 2 x + 1 ( x 2 −2 x + iii ) 2 x −two x ii −2 x + 3 + ii x + 1 ( x ii −2 x + three ) 2

11.5 Matrices and Matrix Operations

1.

A + B = [ 2 1 i half-dozen 0 −3 ] + [ 3 1 −4 −2 5 three ] A + B = [ 2 1 1 6 0 −3 ] + [ three 1 −four −2 5 iii ]
= [ 2 + 3 1 + ane i + ( −iv ) 6 + ( −2 ) 0 + 5 −three + 3 ] = [ five two −three 4 5 0 ] = [ 2 + 3 1 + 1 1 + ( −4 ) 6 + ( −2 ) 0 + 5 −3 + 3 ] = [ 5 2 −3 iv 5 0 ]

2.

−ii B = [ −8 −two −6 −4 ] −2 B = [ −8 −two −half-dozen −4 ]

eleven.6 Solving Systems with Gaussian Elimination

1.

[ 4 −3 3 2 | 11 four ] [ iv −3 three 2 | 11 4 ]

two.

x y + z = 5 2 x y + 3 z = 1 y + z = −9 x y + z = 5 2 x y + 3 z = 1 y + z = −ix

4.

[ 1 5 2 5 ii 0 ane v 0 0 1 | 17 ii 9 ii ] [ one 5 2 five 2 0 i v 0 0 1 | 17 2 ix ii ]

six.

$150,000 at 7%, $750,000 at eight%, $600,000 at 10%

11.vii Solving Systems with Inverses

one.

A B = [ 1 four −1 −3 ] [ −three −iv 1 1 ] = [ 1 ( −3 ) + 4 ( 1 ) 1 ( −4 ) + 4 ( 1 ) −1 ( −3 ) + −3 ( 1 ) −1 ( −iv ) + −3 ( 1 ) ] = [ 1 0 0 1 ] B A = [ −3 −4 1 one ] [ 1 4 −one −iii ] = [ −3 ( i ) + −4 ( −1 ) −3 ( four ) + −4 ( −3 ) 1 ( 1 ) + 1 ( −1 ) one ( 4 ) + ane ( −three ) ] = [ 1 0 0 1 ] A B = [ i 4 −1 −three ] [ −three −four 1 one ] = [ 1 ( −3 ) + iv ( 1 ) 1 ( −iv ) + 4 ( 1 ) −1 ( −3 ) + −3 ( ane ) −one ( −4 ) + −3 ( one ) ] = [ 1 0 0 i ] B A = [ −iii −4 one 1 ] [ 1 4 −one −3 ] = [ −iii ( 1 ) + −4 ( −1 ) −three ( four ) + −4 ( −iii ) 1 ( one ) + 1 ( −1 ) ane ( 4 ) + 1 ( −3 ) ] = [ 1 0 0 1 ]

ii.

A −i = [ 3 5 i 5 ii five 1 five ] A −one = [ 3 5 one 5 2 five i v ]

three.

A −i = [ 1 1 ii 2 4 −iii three vi −v ] A −1 = [ 1 1 two 2 4 −3 3 half dozen −5 ]

4.

Ten = [ four 38 58 ] Ten = [ four 38 58 ]

11.8 Solving Systems with Cramer'due south Dominion

3.

( 2 , three 5 , 12 v ) ( 2 , 3 5 , 12 5 )

xi.1 Section Exercises

1.

No, you lot can either have zero, i, or infinitely many. Examine graphs.

3.

This ways there is no realistic interruption-even indicate. By the fourth dimension the visitor produces i unit of measurement they are already making profit.

five.

You tin can solve by substitution (isolating x x or y y ), graphically, or by add-on.

15.

( 3 v , 0 ) ( 3 5 , 0 )

19.

( 72 5 , 132 v ) ( 72 five , 132 5 )

23.

( 1 2 , ane 10 ) ( i two , 1 ten )

27.

( 1 five , 2 three ) ( ane 5 , 2 3 )

29.

( x , x + 3 two ) ( x , ten + 3 2 )

33.

( 1 2 , 1 8 ) ( i ii , 1 8 )

35.

( 1 6 , 0 ) ( i vi , 0 )

37.

( x , ii ( 7 x −half-dozen ) ) ( x , two ( 7 10 −half-dozen ) )

39.

( 5 half dozen , iv 3 ) ( 5 6 , four three )

41.

Consistent with one solution

43.

Consequent with 1 solution

45.

Dependent with infinitely many solutions

47.

( −3.08 , 4.91 ) ( −3.08 , 4.91 )

49.

( −1.52 , 2.29 ) ( −one.52 , 2.29 )

51.

( A + B 2 , A B 2 ) ( A + B 2 , A B ii )

53.

( −i A B , A A B ) ( −1 A B , A A B )

55.

( C E B F B D A E , A F C D B D A Due east ) ( C E B F B D A Eastward , A F C D B D A E )

57.

They never profit.

59.

( ane , 250 , 100 , 000 ) ( 1 , 250 , 100 , 000 )

61.

The numbers are 7.five and 20.5.

65.

790 sophomores, 805 freshman

69.

10 gallons of x% solution, 15 gallons of 60% solution

71.

Swan Superlative: $750,000, Riverside: $350,000

73.

$12,500 in the outset business relationship, $10,500 in the second account.

75.

High-tops: 45, Depression-tops: xv

77.

Infinitely many solutions. We need more than data.

eleven.2 Section Exercises

ane.

No, there tin be only i, zilch, or infinitely many solutions.

3.

Non necessarily. At that place could be zero, one, or infinitely many solutions. For example, ( 0 , 0 , 0 ) ( 0 , 0 , 0 ) is not a solution to the system below, merely that does not mean that it has no solution.

2 10 + 3 y −6 z = 1 −four ten −6 y + 12 z = −two x + 2 y + v z = 10 2 10 + 3 y −6 z = 1 −four x −half-dozen y + 12 z = −ii x + 2 y + five z = ten

v.

Every organization of equations can be solved graphically, past substitution, and past addition. Withal, systems of three equations become very complex to solve graphically so other methods are usually preferable.

11.

( −1 , 4 , 2 ) ( −1 , 4 , ii )

13.

( 85 107 , 312 107 , 191 107 ) ( 85 107 , 312 107 , 191 107 )

15.

( 1 , 1 2 , 0 ) ( 1 , 1 2 , 0 )

17.

( four , −6 , ane ) ( 4 , −half-dozen , 1 )

nineteen.

( x , ane 27 ( 65 −16 x ) , ten + 28 27 ) ( 10 , ane 27 ( 65 −16 x ) , x + 28 27 )

21.

( 45 thirteen , 17 13 , −2 ) ( 45 thirteen , 17 13 , −ii )

27.

( 4 vii , 1 7 , 3 seven ) ( 4 vii , 1 7 , 3 7 )

29.

( 7 , twenty , 16 ) ( 7 , 20 , 16 )

31.

( −six , 2 , 1 ) ( −half-dozen , 2 , 1 )

33.

( 5 , 12 , xv ) ( five , 12 , 15 )

35.

( −5 , −5 , −five ) ( −five , −5 , −5 )

37.

( 10 , 10 , x ) ( ten , 10 , 10 )

39.

( ane 2 , ane 5 , 4 5 ) ( 1 ii , 1 5 , iv 5 )

41.

( ane two , 2 5 , 4 v ) ( 1 ii , ii 5 , 4 5 )

47.

( 128 557 , 23 557 , 28 557 ) ( 128 557 , 23 557 , 28 557 )

49.

( 6 , −i , 0 ) ( 6 , −1 , 0 )

53.

70 grandparents, 140 parents, 190 children

55.

Your share was $19.95, Sarah'south share was $40, and your other roommate's share was $22.05.

57.

There are infinitely many solutions; we need more information

59.

500 students, 225 children, and 450 adults

61.

The BMW was $49,636, the Jeep was $42,636, and the Toyota was $47,727.

63.

$400,000 in the account that pays 3% interest, $500,000 in the account that pays four% interest, and $100,000 in the account that pays 2% involvement.

65.

The Usa consumed 26.3%, Japan 7.i%, and China 6.4% of the world's oil.

67.

Kingdom of saudi arabia imported 16.8%, Canada imported 15.ane%, and Mexico 15.0%

69.

Birds were nineteen.3%, fish were xviii.six%, and mammals were 17.1% of endangered species

11.3 Section Exercises

ane.

A nonlinear system could be representative of ii circles that overlap and intersect in two locations, hence 2 solutions. A nonlinear system could exist representative of a parabola and a circle, where the vertex of the parabola meets the circle and the branches also intersect the circle, hence three solutions.

3.

No. There does not need to be a feasible region. Consider a system that is bounded by ii parallel lines. One inequality represents the region in a higher place the upper line; the other represents the region below the lower line. In this case, no points in the plane are located in both regions; hence there is no feasible region.

5.

Choose any number between each solution and plug into C ( x ) C ( x ) and R ( ten ) . R ( x ) . If C ( 10 ) < R ( 10 ) , C ( 10 ) < R ( ten ) , then there is profit.

vii.

( 0 , −3 ) , ( iii , 0 ) ( 0 , −three ) , ( iii , 0 )

nine.

( 3 2 ii , three 2 2 ) , ( 3 2 2 , 3 2 2 ) ( iii 2 2 , 3 ii 2 ) , ( 3 2 two , three two 2 )

11.

( −3 , 0 ) , ( 3 , 0 ) ( −three , 0 ) , ( 3 , 0 )

thirteen.

( 1 4 , 62 8 ) , ( 1 iv , 62 8 ) ( 1 4 , 62 8 ) , ( 1 iv , 62 eight )

15.

( 398 4 , 199 4 ) , ( 398 4 , 199 iv ) ( 398 4 , 199 4 ) , ( 398 4 , 199 4 )

17.

( 0 , 2 ) , ( one , 3 ) ( 0 , 2 ) , ( ane , 3 )

xix.

( 1 2 ( 5 −one ) , 1 two ( one 5 ) ) , ( i two ( 5 −1 ) , 1 2 ( 1 5 ) ) ( 1 2 ( 5 −one ) , 1 2 ( one 5 ) ) , ( 1 2 ( five −1 ) , one two ( 1 5 ) )

31.

( 2 two , ii ii ) , ( two 2 , 2 two ) , ( 2 ii , 2 2 ) , ( 2 2 , 2 two ) ( two two , ii 2 ) , ( ii 2 , 2 2 ) , ( two 2 , 2 2 ) , ( ii 2 , 2 two )

35.

( 7 , −3 ) , ( 7 , 3 ) , ( 7 , −3 ) , ( seven , 3 ) ( 7 , −3 ) , ( vii , 3 ) , ( 7 , −3 ) , ( 7 , 3 )

37.

( i 2 ( 73 −5 ) , ane ii ( 7 73 ) ) , ( 1 2 ( 73 −5 ) , 1 ii ( vii 73 ) ) ( 1 2 ( 73 −5 ) , 1 ii ( vii 73 ) ) , ( i 2 ( 73 −5 ) , i ii ( 7 73 ) )

49.

( −ii 70 383 , −2 35 29 ) , ( −2 seventy 383 , 2 35 29 ) , ( 2 70 383 , −2 35 29 ) , ( 2 lxx 383 , 2 35 29 ) ( −2 70 383 , −2 35 29 ) , ( −2 70 383 , 2 35 29 ) , ( 2 seventy 383 , −2 35 29 ) , ( 2 seventy 383 , 2 35 29 )

53.

10 = 0 , y > 0 x = 0 , y > 0 and 0 < x < 1 , x < y < ane x 0 < 10 < 1 , x < y < i x

xi.4 Section Exercises

1.

No, a caliber of polynomials can but be decomposed if the denominator can be factored. For example, 1 10 ii + 1 1 x 2 + one cannot be decomposed because the denominator cannot exist factored.

three.

Graph both sides and ensure they are equal.

v.

If we choose x = −1 , x = −1 , so the B-term disappears, letting us immediately know that A = 3. A = 3. We could alternatively plug in x = 5 three ten = 5 three , giving the states a B-value of −2. −2.

7.

8 x + 3 v 10 −8 viii x + iii five x −eight

9.

1 x + 5 + 9 x + 2 i x + 5 + 9 x + 2

11.

3 5 x −2 + 4 iv x −i 3 5 x −ii + four four x −1

thirteen.

5 2 ( ten + iii ) + 5 two ( 10 −3 ) 5 ii ( x + 3 ) + 5 ii ( 10 −3 )

15.

3 x + 2 + 3 10 −two 3 10 + 2 + 3 x −2

17.

nine 5 ( x + 2 ) + 11 5 ( ten −3 ) 9 5 ( x + 2 ) + 11 5 ( x −3 )

19.

viii x −three v x −ii 8 ten −3 5 x −2

21.

1 x −2 + 2 ( x −2 ) 2 1 x −2 + ii ( x −2 ) ii

23.

vi 4 x + 5 + 3 ( 4 x + 5 ) 2 vi 4 x + 5 + 3 ( 4 ten + 5 ) 2

25.

1 10 −7 2 ( x −seven ) 2 ane 10 −7 2 ( 10 −7 ) 2

27.

4 10 3 2 ( 10 + 1 ) + seven 2 ( x + 1 ) 2 4 x 3 2 ( ten + 1 ) + 7 2 ( 10 + 1 ) two

29.

4 10 + 2 10 2 three three 10 + ii + 7 2 ( 3 10 + 2 ) ii 4 10 + 2 10 2 three 3 x + 2 + seven 2 ( 3 10 + 2 ) 2

31.

x + 1 x two + ten + three + 3 x + ii x + 1 ten 2 + ten + 3 + three x + 2

33.

4 −3 x x 2 + 3 x + viii + 1 ten −1 4 −iii x x 2 + three x + 8 + 1 x −ane

35.

two 10 −1 x 2 + half dozen x + 1 + 2 x + iii two x −1 x two + 6 x + 1 + 2 x + iii

37.

i x 2 + ten + 1 + 4 x −ane one ten ii + ten + 1 + iv x −ane

39.

2 x 2 −3 ten + 9 + 3 x + 3 two x two −iii 10 + nine + 3 x + 3

41.

1 4 x ii + 6 x + 9 + 1 2 x −3 1 4 x 2 + six ten + nine + i 2 x −3

43.

1 x + 1 x + vi iv x x 2 −6 x + 36 1 x + 1 10 + 6 iv ten ten ii −half dozen ten + 36

45.

10 + vi x 2 + 1 + iv x + 3 ( x 2 + 1 ) 2 10 + 6 x 2 + 1 + 4 x + 3 ( x 2 + ane ) 2

47.

x + one ten + 2 + two ten + 3 ( x + 2 ) 2 ten + 1 x + 2 + 2 10 + iii ( ten + 2 ) ii

49.

1 x two + 3 x + 25 3 x ( x 2 + 3 x + 25 ) ii i x ii + 3 10 + 25 3 ten ( 10 2 + 3 x + 25 ) 2

51.

1 viii 10 ten 8 ( x two + 4 ) + 10 x 2 ( x 2 + 4 ) two 1 eight x x 8 ( x 2 + 4 ) + 10 10 2 ( x 2 + 4 ) 2

53.

16 ten ix x ii + 16 x −1 seven ( 10 −i ) 2 xvi 10 9 x 2 + 16 x −ane 7 ( x −i ) 2

55.

1 x + i 2 ( x + 1 ) 2 + five ( x + 1 ) iii 1 x + one two ( x + 1 ) two + 5 ( x + one ) three

57.

5 ten −ii iii 10 ( x + 2 ) + 7 ten + eight vii 10 ( ten −8 ) v ten −2 iii 10 ( x + 2 ) + vii 10 + viii vii 10 ( x −8 )

59.

5 iv x 5 two ( 10 + 2 ) + 11 two ( 10 + 4 ) + 5 4 ( x + 4 ) 5 4 ten 5 two ( x + 2 ) + xi 2 ( x + 4 ) + 5 4 ( 10 + 4 )

11.5 Section Exercises

1.

No, they must have the same dimensions. An example would include two matrices of different dimensions. One cannot add together the post-obit two matrices because the first is a 2 × two 2 × two matrix and the second is a 2 × iii 2 × three matrix. [ i 2 three iv ] + [ half dozen 5 iv 3 two one ] [ one two 3 4 ] + [ 6 5 four 3 2 ane ] has no sum.

3.

Yes, if the dimensions of A A are thousand × n g × n and the dimensions of B B are northward × m , n × m , both products will exist divers.

five.

Non necessarily. To find A B , A B , we multiply the first row of A A past the first cavalcade of B B to get the get-go entry of A B . A B . To observe B A , B A , we multiply the first row of B B past the showtime column of A A to get the first entry of B A . B A . Thus, if those are unequal, and then the matrix multiplication does not commute.

7.

[ xi 19 15 94 17 67 ] [ xi 19 15 94 17 67 ]

9.

[ −4 two 8 1 ] [ −iv ii 8 1 ]

11.

Undidentified; dimensions practise non match

13.

[ ix 27 63 36 0 192 ] [ 9 27 63 36 0 192 ]

15.

[ −64 −12 −28 −72 −360 −20 −12 −116 ] [ −64 −12 −28 −72 −360 −20 −12 −116 ]

17.

[ i , 800 1 , 200 1 , 300 800 1 , 400 600 700 400 two , 100 ] [ 1 , 800 1 , 200 ane , 300 800 1 , 400 600 700 400 two , 100 ]

19.

[ twenty 102 28 28 ] [ 20 102 28 28 ]

21.

[ 60 41 2 −16 120 −216 ] [ threescore 41 2 −16 120 −216 ]

23.

[ −68 24 136 −54 −12 64 −57 30 128 ] [ −68 24 136 −54 −12 64 −57 30 128 ]

25.

Undefined; dimensions do not match.

27.

[ −viii 41 −iii twoscore −fifteen −14 4 27 42 ] [ −8 41 −3 40 −xv −xiv 4 27 42 ]

29.

[ −840 650 −530 330 360 250 −10 900 110 ] [ −840 650 −530 330 360 250 −10 900 110 ]

31.

[ −350 one , 050 350 350 ] [ −350 1 , 050 350 350 ]

33.

Undefined; inner dimensions practice not match.

35.

[ i , 400 700 −1 , 400 700 ] [ 1 , 400 700 −one , 400 700 ]

37.

[ 332 , 500 927 , 500 −227 , 500 87 , 500 ] [ 332 , 500 927 , 500 −227 , 500 87 , 500 ]

39.

[ 490 , 000 0 0 490 , 000 ] [ 490 , 000 0 0 490 , 000 ]

41.

[ −2 3 4 −seven 9 −7 ] [ −two 3 4 −7 nine −7 ]

43.

[ −4 29 21 −27 −iii ane ] [ −4 29 21 −27 −3 i ]

45.

[ −3 −2 −2 −28 59 46 −four 16 7 ] [ −3 −2 −2 −28 59 46 −4 16 7 ]

47.

[ 1 −18 −9 −198 505 369 −72 126 91 ] [ ane −18 −9 −198 505 369 −72 126 91 ]

49.

[ 0 1.6 nine −i ] [ 0 ane.vi 9 −1 ]

51.

[ 2 24 −4.5 12 32 −9 −eight 64 61 ] [ 2 24 −4.v 12 32 −ix −viii 64 61 ]

53.

[ 0.5 3 0.5 2 1 2 10 7 ten ] [ 0.5 3 0.5 2 1 2 10 seven x ]

55.

[ i 0 0 0 1 0 0 0 i ] [ i 0 0 0 one 0 0 0 ane ]

57.

[ 1 0 0 0 i 0 0 0 1 ] [ 1 0 0 0 i 0 0 0 one ]

59.

B n = { [ 1 0 0 0 i 0 0 0 1 ] , due north even, [ 1 0 0 0 0 1 0 ane 0 ] , n odd . B n = { [ 1 0 0 0 1 0 0 0 1 ] , n even, [ 1 0 0 0 0 1 0 1 0 ] , north odd .

11.vi Section Exercises

1.

Yes. For each row, the coefficients of the variables are written beyond the corresponding row, and a vertical bar is placed; then the constants are placed to the correct of the vertical bar.

3.

No, there are numerous correct methods of using row operations on a matrix. Ii possible means are the following: (one) Interchange rows i and 2. Then R 2 = R 2 −nine R 1 . R ii = R 2 −nine R 1 . (2) R 2 = R one −9 R 2 . R two = R 1 −nine R 2 . Then divide row 1 by 9.

5.

No. A matrix with 0 entries for an entire row would accept either nil or infinitely many solutions.

vii.

[ 0 sixteen 9 −1 | 4 2 ] [ 0 16 nine −1 | 4 two ]

nine.

[ 1 5 8 12 3 0 3 4 ix | sixteen 4 −vii ] [ 1 v 8 12 3 0 3 4 9 | 16 4 −seven ]

11.

−2 ten + 5 y = 5 6 x −eighteen y = 26 −2 x + 5 y = v half-dozen x −xviii y = 26

13.

3 10 + two y = 3 x −nine y + 4 z = −1 8 10 + 5 y + 7 z = eight 3 10 + 2 y = three 10 −nine y + 4 z = −ane 8 10 + v y + 7 z = viii

15.

4 10 + 5 y −two z = 12 y + 58 z = ii 8 x + 7 y −3 z = −v 4 10 + 5 y −2 z = 12 y + 58 z = 2 8 x + 7 y −iii z = −5

25.

( i 5 , 1 2 ) ( 1 five , 1 2 )

27.

( ten , 4 15 ( five 10 + ane ) ) ( x , 4 xv ( 5 10 + 1 ) )

31.

( 196 39 , 5 13 ) ( 196 39 , v 13 )

33.

( 31 , −42 , 87 ) ( 31 , −42 , 87 )

35.

( 21 40 , 1 20 , 9 viii ) ( 21 twoscore , i 20 , 9 8 )

37.

( eighteen 13 , 15 13 , 15 13 ) ( 18 13 , xv 13 , xv 13 )

39.

( x , y , 1 2 ( i −2 ten −3 y ) ) ( x , y , i ii ( 1 −ii x −3 y ) )

41.

( x , 10 2 , −i ) ( x , x 2 , −1 )

43.

( 125 , −25 , 0 ) ( 125 , −25 , 0 )

45.

( 8 , one , −2 ) ( viii , 1 , −two )

49.

( x , 31 28 iii x four , 1 28 ( −7 x −3 ) ) ( ten , 31 28 three 10 4 , 1 28 ( −7 x −3 ) )

53.

860 cerise velvet, 1,340 chocolate

55.

4% for business relationship ane, six% for business relationship 2

59.

Banana was 3%, pumpkin was seven%, and rocky route was 2%

61.

100 almonds, 200 cashews, 600 pistachios

11.7 Department Exercises

1.

If A −1 A −1 is the inverse of A , A , then A A −ane = I , A A −ane = I , the identity matrix. Since A A is besides the inverse of A −i , A −one A = I . A −one , A −one A = I . You tin also check by proving this for a two × two ii × 2 matrix.

3.

No, because a d a d and b c b c are both 0, so a d b c = 0 , a d b c = 0 , which requires us to separate by 0 in the formula.

5.

Yes. Consider the matrix [ 0 1 1 0 ] . [ 0 1 1 0 ] . The inverse is institute with the following calculation: A −i = 1 0 ( 0 ) −ane ( 1 ) [ 0 −1 −1 0 ] = [ 0 one one 0 ] . A −1 = 1 0 ( 0 ) −1 ( one ) [ 0 −one −one 0 ] = [ 0 i i 0 ] .

7.

A B = B A = [ 1 0 0 one ] = I A B = B A = [ 1 0 0 1 ] = I

nine.

A B = B A = [ one 0 0 ane ] = I A B = B A = [ one 0 0 i ] = I

11.

A B = B A = [ 1 0 0 0 i 0 0 0 1 ] = I A B = B A = [ i 0 0 0 1 0 0 0 one ] = I

13.

1 29 [ 9 ii −1 3 ] 1 29 [ ix 2 −1 3 ]

15.

1 69 [ −2 7 ix 3 ] 1 69 [ −two vii 9 3 ]

xix.

4 7 [ 0.five 1.5 i −0.five ] 4 7 [ 0.five 1.5 1 −0.five ]

21.

1 17 [ −5 5 −3 20 −iii 12 ane −ane four ] i 17 [ −five v −3 20 −3 12 i −1 4 ]

23.

1 209 [ 47 −57 69 10 19 −12 −24 38 −13 ] 1 209 [ 47 −57 69 10 19 −12 −24 38 −thirteen ]

25.

[ eighteen threescore −168 −56 −140 448 40 80 −280 ] [ 18 lx −168 −56 −140 448 40 lxxx −280 ]

31.

( 1 iii , 5 2 ) ( 1 iii , 5 2 )

33.

( ii 3 , 11 6 ) ( 2 three , xi 6 )

35.

( seven , 1 2 , 1 five ) ( vii , 1 2 , 1 5 )

37.

( five , 0 , −ane ) ( v , 0 , −1 )

39.

1 34 ( −35 , −97 , −154 ) 1 34 ( −35 , −97 , −154 )

41.

1 690 ( 65 , −1136 , −229 ) 1 690 ( 65 , −1136 , −229 )

43.

( 37 30 , viii xv ) ( 37 30 , 8 15 )

45.

( 10 123 , −1 , 2 5 ) ( 10 123 , −one , two five )

47.

1 2 [ ii ane one i 0 1 1 1 0 1 1 1 0 1 1 1 ] i 2 [ 2 1 1 1 0 1 1 1 0 1 1 one 0 ane ane one ]

49.

one 39 [ iii 2 i 7 18 53 32 10 24 36 21 nine ix 46 16 5 ] ane 39 [ 3 2 1 7 xviii 53 32 10 24 36 21 9 9 46 xvi 5 ]

51.

[ i 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 ane 0 1 one one one 1 i ] [ 1 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 ane 0 0 0 0 0 0 1 0 one 1 1 1 ane 1 ]

55.

50% oranges, 25% bananas, xx% apples

57.

x harbinger hats, 50 beanies, forty cowboy hats

59.

Tom ate 6, Joe ate 3, and Albert ate 3.

61.

124 oranges, x lemons, viii pomegranates

11.8 Section Exercises

one.

A determinant is the sum and products of the entries in the matrix, so you tin ever evaluate that product—fifty-fifty if it does end up being 0.

three.

The inverse does not exist.

27.

( ane 2 , 1 3 ) ( i ii , 1 three )

31.

( 1 , ane 3 ) ( i , ane 3 )

37.

( ane , 0 , 3 ) ( i , 0 , 3 )

39.

( 1 2 , i , 2 ) ( 1 2 , 1 , 2 )

53.

$seven,000 in first account, $3,000 in second account.

55.

120 children, 1,080 adult

57.

4 gal yellow, vi gal bluish

59.

13 green tomatoes, 17 red tomatoes

61.

Strawberries 18%, oranges 9%, kiwi 10%

63.

100 for pic i, 230 for movie two, 312 for moving-picture show 3

65.

20–29: ii,100, thirty–39: two,600, 40–49: 825

67.

300 almonds, 400 cranberries, 300 cashews

Review Exercises

9.

( 300 , threescore , 000 ) ( 300 , sixty , 000 )

15.

( 1 , 2 , iii ) ( 1 , 2 , 3 )

17.

( x , 8 x v , 14 10 five ) ( 10 , 8 ten v , 14 x 5 )

21.

( 2 , 3 ) , ( iii , 2 ) ( ii , 3 ) , ( iii , 2 )

31.

2 x + ii , iv x + 1 ii 10 + 2 , 4 x + ane

33.

vii x + 5 , xv ( 10 + 5 ) 2 seven x + 5 , 15 ( x + 5 ) ii

35.

3 x 5 , four x + 1 10 2 + five x + 25 3 x five , 4 10 + ane x 2 + 5 ten + 25

37.

x 4 ( x 2 two ) , 5 x + 3 ( ten 2 2 ) two 10 4 ( x two 2 ) , 5 x + 3 ( x ii 2 ) 2

39.

[ sixteen 8 4 12 ] [ sixteen viii four 12 ]

41.

undefined; dimensions do non friction match

43.

undefined; inner dimensions exercise not match

45.

[ 113 28 10 44 81 41 84 98 42 ] [ 113 28 ten 44 81 41 84 98 42 ]

47.

[ 127 74 176 two 11 forty 28 77 38 ] [ 127 74 176 ii eleven xl 28 77 38 ]

49.

undefined; inner dimensions do not match

51.

x 3 z = 7 y + 2 z = five 10 3 z = 7 y + 2 z = 5 with infinite solutions

53.

[ 2 ii i 2 8 five xix 10 22 | seven 0 three ] [ ii 2 i ii 8 five 19 10 22 | 7 0 3 ]

55.

[ 1 0 3 −one 4 0 0 1 2 | 12 0 −7 ] [ 1 0 3 −one 4 0 0 1 2 | 12 0 −vii ]

61.

1 8 [ two vii 6 1 ] i 8 [ two vii 6 i ]

65.

( twenty , 40 ) ( 20 , 40 )

67.

( 1 , 0.2 , 0.3 ) ( 1 , 0.two , 0.iii )

69.

17% oranges, 34% bananas, 39% apples

75.

( half-dozen , i ii ) ( 6 , 1 ii )

79.

( 0 , 0 , 1 2 ) ( 0 , 0 , 1 two )

Do Examination

five.

ane 20 ( 10 , 5 , 4 ) 1 20 ( 10 , v , 4 )

7.

( x , 16 ten 5 13 x v ) ( 10 , 16 x 5 13 10 5 )

nine.

( 2 2 , 17 ) , ( 2 2 , 17 ) , ( ii 2 , 17 ) , ( 2 2 , 17 ) ( 2 2 , 17 ) , ( ii 2 , 17 ) , ( 2 two , 17 ) , ( 2 2 , 17 )

13.

five 3 x + 1 two x + 3 ( 3 x + ane ) two 5 3 x + ane 2 x + 3 ( iii x + 1 ) two

xv.

[ 17 51 8 eleven ] [ 17 51 eight xi ]

17.

[ 12 20 fifteen 30 ] [ 12 20 15 xxx ]

21.

[ 14 2 13 2 3 six 1 5 12 | 140 1 eleven ] [ 14 2 13 2 3 6 1 5 12 | 140 one xi ]

25.

( 100 , 90 ) ( 100 , 90 )

27.

( 1 100 , 0 ) ( 1 100 , 0 )

29.

32 or more cell phones per day

1-4 Exercises Guided Practice Geometry,

Source: https://openstax.org/books/algebra-and-trigonometry/pages/chapter-11

Posted by: daltonbroand1990.blogspot.com

0 Response to "1-4 Exercises Guided Practice Geometry"

Post a Comment

Iklan Atas Artikel

Iklan Tengah Artikel 1

Iklan Tengah Artikel 2

Iklan Bawah Artikel